completing a circuit based on 12v power

Hi all,

I am wiring an old car of mine up with a cheap push button start after the ignition switch died.

I have already gotten everything working, with one issue - my immobilizer. Looking to do this as cheaply as possible, I have attached the transponder to the factory transponder ring.

My car functions and starts with the button.. however, I cannot lock the doors as the transponder is always detected as being present.

I need a way to "break" the loop that runs to the security module to trick it into thinking the key (transponder) has been removed.

I tried a 4-post relay (Dorman 84601) with my "ON" wire (hot except when car is off) cut in half. I connected the cut ends to 86 and 86... then connected the cut transponder ring wire to 30 and 87. I heard the relay activate, but my "ON" wire didn't make it past the relay to power anything and the transponder signal didn't make it through either.


How can I do this correctly?

Seemed like this relay would have done the trick - giving it 12V should complete the second circuit thus "turning on" the transponder signal. I have a feeling that my understanding of how this should be wired is flawed.

chrisificti0n wrote:

---

I tried a 4-post relay (Dorman 84601) with my "ON" wire (hot except when car is off) cut in half. I connected the cut ends to 86 and 86..........

but my "ON" wire didn't make it past the relay to power anything

---

I'm not exactly following what you're trying. BUT I think I see a flaw in the above.

You do not cut the "ON" wire in two. You "tap" it by attaching a wire TO it, and that wire goes to 86 on the relay. 85 goes to a chassis ground.

The way you did it with the cut wire put the relay coil in series with what your trying to power with the "ON" wire. The "ON" stuff won't see any voltage this way.

Begin with redoing the way you connected 85 and 86. 85 to ground, and 86 to "ON".