momentary to constant?

Hey all, been awhile since I have been around, I have a question. I am trying to make a circuit to where a momentary ground will make a signal turn on, and stay on when the car is in ON or ACC, and shut off when the key is removed. I seen this with the relay explanations and what not, and wondering if this would work . . . IMG]https://www.the12volt.com/12voltimages/momentconstant.gif[/IMG] Here is what I was thinking would work. relay #1 85 - negative (-) pulse 86 - fused constant 12v+ 30 - fused constant 12v+ 87 - to #30 of relay #2 relay #2 85 - constant ground 86 - constant 12v+ 30 - from 87 of relay #1 87 - to # 85 of relay #3 relay #3 85 - from 87 of relay #2 86 - constant ground 30 - constant fused 12v+ 87 - (newly interupted when not switched on output shut off with key) That is the correct way of accomplishing what I asked correct? Thanks all!Eclipse 8445, Kicker DS60's, Hifonics TXi4400, Eclipse SW6143DVC, and Power Acoustik LT980-2.

You could do it this way- 85 - negative (-) pulse 86 - IGN switched 12v+ 30 - IGN switched 12v+ 87 - to #85 of relay #2 relay #2 85 - from 87 of relay #1 86 - constant ground 30 - IGN switched 12v+ 87 - to # 85 relay #2 Diode between 87 and 85 of relay #2, stripe towards 85 Your 12V output will be terminal 87 of relay #2, which turns on when you give it the momentary ground pulse with the ignition on, and turns off when you shut the ignition off.

thanks a lot for that, it will save me a relay or $2 lol! :)Eclipse 8445, Kicker DS60's, Hifonics TXi4400, Eclipse SW6143DVC, and Power Acoustik LT980-2.

Actually, you don't even need the diode, just connect 85 and 87 directly, just as the diagram shows.