figuring RMS

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doc t

Copper - Posts: 169

Joined: April 11, 2004

Location: South Carolina, United States

Posted: May 19, 2004 at 6:26 AM / IP Logged

I know I've seen a thread about this in the past...but can't find it now...What is the best and most sure fire way to figure out how many WRMS a low end amp puts out, if it only gives you max wats, peak output?

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stevdart

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Joined: January 24, 2004

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Posted: May 19, 2004 at 9:01 AM / IP Logged

Similar to the thread you referred to, you can use your multimeter to read output voltage. Power in watts = voltage squared / ohms resistance. Refer to Ohm's Law calculations to find power. Read with test tones for a steady volt reading. But the sure-fire way is this, if you have an oscilloscope and all this stuff to work with.

Build the box so that it performs well in the worst case scenario and, in return, it will reward you at all times.

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haemphyst

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Posted: May 19, 2004 at 9:07 AM / IP Logged

multiply the input fuse value by 14.4, divide by 4. this assumes a 50 percent efficiency. example: 20amp fuse x 14.4 = 288 / 2 = 72 watts RMS per channel (engine runing. multiply by 12 for engine off ratings). this'll get you close to a real output value. double that number, will give you close to a peak, low distortion (>10 percent distortion) output.

It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

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doc t

Copper - Posts: 169

Joined: April 11, 2004

Location: South Carolina, United States

Posted: May 19, 2004 at 9:25 AM / IP Logged

and to find bridged rms values just multiply rms output for two ch. by 2. ex: 72x2=144 bridged rms?

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figuring RMS

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