Hey!
I am just wondering how you would figure out the RMS of an amplifier without a big huge test bench or whatever manufactures use. I just want to know exactly what I am running and stuff. If anyone knows a formula, please let me know.
Thanks!!
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Soccer_aholic:^:
well, if its got fuses on the side of the amp, whatever its rated at, add a zero to the end of it, such as.. as 20 amp fuse would be 200 watts. That would be the peak power output that the amp would be capable of, before blowing the fuse, so just cut that number in half. that would be the easiest way to do it. but if you want the real, deal, just wait, im sure DY or Rob will know the answer for ya.
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1990 Honda Civic HB:
Clarion DXZ545MP H.U.
2- 6.5" Power Acoustik interiors
Diamond Audio 600.1 amp
Diamond Audio 15" M6MKII
Pyramid PB881X 4 CH. Amp
Use the Ohm's Law formula P = E squared / R https://www.the12volt.com/ohm/page2.asp
With a DMM, measure the AC output voltage at the speaker terminals, square that number, then divide that by the ohm load that the amp sees from the speaker(s). That will give the RMS going to that speaker load.
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Build the box so that it performs well in the worst case scenario and, in return, it will reward you at all times.
Cool that makes it really easy...on my amp (Alpine MRD-M500) it shows the voltage and the current. So that will be easy...cuz all it is the voltage multiplied by the current. so that will give me the power it is putting out at that time. So basically let me see if i get this straight....I take the voltage multiply it by the current to get the power. I then take what?? How are your two statements realated? or are they. Does one just give me power and the other give me RMS? I am confused...I apologize if this is stupid and I should get it.
Thanks for your help and prompt reply
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Soccer_aholic
P = Power = RMS Watts..............same thing.
The reason you use a multimeter to make your own reading of the amp's output voltage is to see what voltage the amp is making in the REAL world. Don't just read what's on the amp.
Then apply it to the formula. I said one thing, not two different things.
P = E squared divided by R ..........or.........same as..........
RMS Watts = Voltage squared divided by Ohms
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Build the box so that it performs well in the worst case scenario and, in return, it will reward you at all times.
ah! i get it now. my apologies. i knew it was there i just couldnt get my mind around what you were saying. thanks again for all your help.
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Soccer_aholic