WIRING DUAL VOICE COILS SPECIALTY
Printed From: the12volt.comForum Name: Car Audio
Forum Discription: Car Stereos, Amplifiers, Crossovers, Processors, Speakers, Subwoofers, etc.
URL: https://www.the12volt.com/installbay/forum_posts.asp?tid=40777
Printed Date: July 21, 2025 at 9:51 AM
Topic: WIRING DUAL VOICE COILS SPECIALTY
Posted By: uthinkuknoaudio
Subject: WIRING DUAL VOICE COILS SPECIALTY
Date Posted: October 12, 2004 at 9:52 PM
Replies:
Posted By: stevdart
Date Posted: October 12, 2004 at 10:00 PM
For a two ohm load, the voice coils are wired in series. Then the woofers are paralleled to the amp.
The first question was easy enough. The second is a doozy...but you asked about quad coils and then asked about DVC... what do you have, exactly?
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Build the box so that it performs well in the worst case scenario and, in return, it will reward you at all times.
Posted By: uthinkuknoaudio
Date Posted: October 12, 2004 at 10:15 PM
Posted By: stevdart
Date Posted: October 12, 2004 at 10:56 PM
I'll cover the DVC part, but I'll leave the quads alone because I've never dealt with those. This is just for the six 6-ohm drivers, but the same rationale follows for other impedances. To get the highest possible load, wire in series/series. A wire from the pos on the amp goes to the first woofer, coil one pos. Coil one neg goes to coil two pos, then coil two neg goes to the second woofer coil one pos. And so on, until the last terminal goes back to the amp neg.
Everything is added up. Each woofer has 12 ohms (coils in series), and there are 6 woofers in series. 12 X 6 = 72 ohms, the highest load.
2nd: parallel/series: Like the wiring shown in the top diagram here...NOTE: the values of the voice coils and the number of woofers are different than your scenario. Use these two following diagrams as indicators of wiring and nothing else.
The woofers are dual 6 ohm, so their value will be 3 ohms each (coils in parallel). Wiring in series back to the amp is multiplying 3 (ohms) X 6 (woofers) = 24 ohms.
3rd: series/parallel, like the diagram in option 2 above. In this case the individual woofers would each be 12 ohms (coils in series), then when paralleled back to the amp you figure on dividing instead of multiplying. So 12 (ohms) divided by 6 (woofers) = 2. You would have a 2 ohm load.
4th: parallel/parallel.
Like this illustration, the coils are first wired in parallel. Each woofer becomes a 3-ohm load. You have 6 woofers (in parallel), so the math is: 3 (ohms) divided by 6 (woofers) = 0.5 ohms.
Those are all the possibilities, but you can see that only one...series/parallel...is actually feasable in this particular case.
https://www.sounddomain.com/shop/wooferwizard.pl
https://www.rockfordfosgate.com/rftech/wiringwizard.asp
https://www.bcae1.com/srsparll.htm
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Build the box so that it performs well in the worst case scenario and, in return, it will reward you at all times.
Posted By: uthinkuknoaudio
Date Posted: October 13, 2004 at 11:19 AM
Posted By: DYohn
Date Posted: October 13, 2004 at 11:34 AM
Posted By: uthinkuknoaudio
Date Posted: October 13, 2004 at 4:57 PM
Posted By: DYohn
Date Posted: October 13, 2004 at 5:12 PM
Posted By: tbirdman74
Date Posted: October 14, 2004 at 6:14 PM