dual 4-ohm L5, 800.2 Kicker Amp

Hey you guys,

I've got a question for the wiring EXPERTS... I have a dual 4-ohm Kicker L5 that is wired in Parallel (2-ohm Load) to a bridged 800.2 Kicker Amp. Yes, thats right..and 800.2. You can kick me later :oops:. I bought the amp during my high school days when more power is the greatest thing in the world and now down graded to a single sub. Just wondering what load I am putting on the amp?

I was told by Kicker reps when setting up the system that the amp would shut off. Hasn't yet. So I'm wondering what they worries were and why.

My system consist of;

HU: Fosgate (9200 I think, not proud of but to cheap to buy new right now)

Crossover: Kicker KQ5 (Using for the Sub-sonic filter as the 800.2 does not have one)

Amp: Kicker 800.2 (Bridged)

Sub: Kicker L5 (Dual 4-ohm - Paralleled)

Everything is actually in a custom design box. It doesn't look like anything but it is truly designed for my vehicle with the correct parameters. If you have any questions about a box for a Grand Am or Jeep Cherokee just give me a shout out and I'll send you everything you should need for a certain sub setup.

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If your counting pennies and dimes then maybe you shouldn't be spending every penny and dime you have!!

One ohm per channel

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It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

Thanks for your reply. Just wondering then, I obviously am not a Car Audio idiot but I'm not really all to familier with a setup like this. So I have a 2-ohm load coming from the sub, but then when I bridged the amp that cut that load in half down to a 1-ohm load correct? I'm actually a Mechanical Engineering student so I'm trying to truley understand all of this through formulas and numbers but can't really seem to get a grasp. I thought that the sub or subs determined the load that was placed on the amp. But your saying that with this setup that the amp actually then cuts that load in half. Could you explain this in a little more detail perhaps.

If anyone else could answer this, feel free to let me hear it...

Thank you,

Jon

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If your counting pennies and dimes then maybe you shouldn't be spending every penny and dime you have!!

When you bridge an amplifier, you are doubling the voltage (and therefore the current) across the load. This is how you create (in theory) 4 times the power. This doubling of current demand is where the "halving" of the impedance takes place. You are mot MECHANICALLY adding additional load with more speakers, but electrically "adding load", by increasing the power produced.

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It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

Hey that defiantly makes perfect sense. Thanks for explaining it clearly to me. Truly appreciate it. Kinda shows why I'm a MECHANICAL engineer and not an electrical engineer..

Thanks again,

Jon

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If your counting pennies and dimes then maybe you shouldn't be spending every penny and dime you have!!