Converting 4 ohm speaker to 8 ohm

Can I put a 4 ohm resistor in series on each 4 ohm speaker to make it an 8 ohm circuit?

Thanks

Aaron

I dont think that's a good idea. you basically cut the voltage in 1/2. means you cut your watts in 1/2.

Why dont you tell us what you need to accomplish and maybe we can help. :)

What if the speakers were bridged so I could have more watts?

Thanks

Aaron

usually the amp can put out more watts if your impetance is low. are you trying to  connect the speakers in series? so you can have 4ohm +4 ohm = 8ohm? I dont see what good that will do and the truth..i've never done that. I've connect speakers in parallel. which 1/4 + 1/4 = 1/x which = 2 ohm load which most amp that can handle 2 ohm load will put out more than 4 ohm.

Be more specific and detail of what you're doing. tell me about your amp. your speakers. etc

The amp is a mtx pro75x2 here are its specs

RMS Power measured at 12.5 Volts DC:
37.5 watts x 2 into a 4 ohm load with less than 0.05% THD+N
75 watts x 2 into a 2 ohm load with less than 0.1% THD+N
150 watts bridged into a 4 ohm load with less than 0.1% THD+N

Dynamic Power (IHF-202 standard) measured at 14.4 Volts DC:
90 watts x 2 into a 4 ohm load
165 watts x 2 into a 2 ohm load
325 watts bridged into a 4 ohm load

The speakers are a 12" kenwood

Impedance: 4 ohms,  Power Handling: 700 Watts, and I think 175 watts rms

The head unit is a kenwood kdc-519

I'm new at this but, a buddy of mine made the suggestion since my speakers weren't 8 ohm.  And see, the amp will put out 325 watts bridged into a 4 ohm load.  So, if the speakers were connected in parallel and, in this particular case 1/8 +1/8=1/x   where,  x would equal the 4 ohm load which, my amp is designed for.  Like i said, I am new at this and I don't know.  It seems like it would work (in theory) if i could find a resistor to carry all the wattage but, any help would be appreciated.  

Thanks

Aaron