crazy amplifier application

Ok I came up with this idea at work.
Is it possible to run one amp for subs, and another amp for some other accessory.
I was thinking use my amp for power a hydraulic pump, or an electric air compressor so that I can have a tricked out truck.
I dont see why not, electricity is electricity, as long as my amp has enough power to run something, why wouldnt that work?
Thanks

Well for one thing the impedence on the pump or compressor would have be in the amps tolerences.

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There is no such thing as free installation!

hmmm....yes it would have to be thats right.
That could be only a little difficult to match up, but certainly possible given the vast selection of products out there.

Have you ever seen something like that?
I mean batteries power hydro's all the time

Don't really see WHY you would need the amp. Aren't these products available in 12 volt versions?

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There is no such thing as free installation!

Yes, it can be done. I have actually run a vaccuum off an Adcom GFA565 in bridged mode. It was really cool, because I was driving the input with a sine-wave generator, and you could hear the efficiency of the vaccuum's motor improve or reduce with the frequency. The amp ran hot as HELL, but the Adcoms are quite capable devices, and I just ran a fan on the heatsinks for the rest of the experiments. I thought I was the only person that thought like that :)

But tcss is right, most anything you could need SHOULD be available in a 12V version... It would CERTAINLY be cheaper than buying an amplifier with the required capabilities, I think.

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It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

Well what can I say , I like thinking out in left field!

yea the only catch wuold be keeping the amp output at a certain level. be easier to just get a converter, fairly cheap. like a 1400 watt for around 50 bucks would power most things .

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05 Neon SXT/infinity 311a/2 Polk db104 subs/vr3 400 watt to factory front and rear

Are you saying you're going to take an AC hydraulic pump that requires 120V @ 60 hz, hook it up to your amp and you want to know if there is something wrong with doing that? Amazing.

zerorearfill wrote:

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Are you saying you're going to take an AC hydraulic pump that requires 120V @ 60 hz, hook it up to your amp and you want to know if there is something wrong with doing that? Amazing.

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Interested to know why you think it can't happen... I can tell you that it CAN happen. If the amp is capable of producing the required voltage, across the presented load, why, again, do you think it can't work?

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It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

well,
Looking at various automotive hydraulic pumps you'll need one with an output of around 1/5hp, which equals about 150W, to do anything. Now, let's look at two differnet scenarios; The first one we'll assume your amp is outputting 120V and the pump is consuming 150W. That means you'll have to find a pump with a resistence of 96 OHMs. I wouldn't be able to find you an amp that outputs 150W at 96 OHMs. For the second scenario, we'll assume you find a 4 ohm hydraulic pump. To sustain a voltage of 120v your amp will need to output 3600 watts continuously.
Also, output from a power plant can be assumed to be EXACTLY 60hz. With the distortion of your amplifier added to the output signal, I doubt you can be quite so confident.
The only things I can see you powering with an amplifier, other than what it was meant to, would be a tiny lightbulb or a very small motor.

JBL has a video of one of there amps powering a hack saw to cut another amp in half...pretty cool

What is the life of a hacksaw being powered by an amp? are there any modifications made to the hacksaw? is the video altered?

zerorearfill wrote:

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What is the life of a hacksaw being powered by an amp?

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Ummm.... Like the OP says, electricity is electricity. Why would the life of the saw be any different? If the power applied is correct, meaning correct voltage, current and frequency, whether it comes from an amplifier output stage or the wall, what's the difference??

zerorearfill wrote:

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are there any modifications made to the hacksaw?

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No. I've seen the video... I'll try to dig up the link for you. It's a standard Sawz-All.

zerorearfill wrote:

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is the video altered?

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As a marketing gimmick, I can see how you would think that Harman would WANT to alter it, but, as I said, I've seen it, and I could sense no alteration.

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It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

I'm obviously talking to a group of electrical engineers here, so I'll shut my mouth.

zerorearfill wrote:

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I'm obviously talking to a group of electrical engineers here, so I'll shut my mouth.

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Dude, don't take it like that... We're all here to help with understaning. I was just trying to find out WHERE you weren't understanding so I could help in that respect...

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It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

I was kidding. Have fun getting worked over. Bye.

Cutting through another amp? Sweet!! I'd love to have a job where I get to do that.
One other thing why I think it would work, is because it would only require a short burst of power because the hydro pump would not be in use for more then a second or two. Maybe I could incorporate a 1 farad cap??
Also, does anyone know how to figure out how many volts an amp would be putting out from the amps watt rating?
Thanks

rockford used a two channel amp to power a sub and a blender at a training I was at once... tasty margarita!

3000dClass-

Yes, but only if the impedance or amperage are known.

P=I*V
V=I*R

P = Watts
V = Voltage
I = Amps
R = Resistance

Using the above equations we go from V=I*R to I = V/R.
P = I*V, so substituting P = (V/R)*V.
Simplifying, P = V^2/ R and ultimately:
V = sqrt(P * R)

Therefore, for 100 watts @ 4 ohms (typical speaker load)
V = sqrt(400) = 20 volts.

d-

zerorearfill wrote:

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I was kidding. Have fun getting worked over. Bye.

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Hahaha! -Haven't you seen the given formulas?

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2013 Kia Rio -90a alternator
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