Enclosure volume = 2.5 cu. ft.
40 square inches of port area. how long would i make the port to tune the box to 32 hz?
thanks in advance.
or could anyone give me the formula to figure this out??? (sry about the dbl post.)
40 sq-inches is equivalent to a 7.14" round port. (40 divided by pi = 12.75. Square root of 12.75 = 3.57" which would be the radius. 3.57 X 2 = 7.14" diameter) Using the port length calculator on this site (
LINK to the left) = port length 36.927" That's a lot of port length in a small enclosure. I recommend making your port opening half that size, then your length will be just under eight-inches.
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Support the12volt.comthe manufacturer suggest 12-16 sq. in. of port area per cu. ft of volume. what would be the drawbacks of using a 19.625 sq. in. port that is 17 in. long? would there be any audible difference, meaning port noise. i could just run the port along the outside walls of the enclosure to get it to fit because i want to avoid port noise if at all possible. also i have another question. when taking the port into consideration for enclosure volume, i would really need a box that is 2.5 cu. ft plus the volume of the port, correct?
kamberkash wrote:
the manufacturer suggest 12-16 sq. in. of port area per cu. ft of volume. what would be the drawbacks of using a 19.625 sq. in. port that is 17 in. long? would there be any audible difference, meaning port noise. i could just run the port along the outside walls of the enclosure to get it to fit because i want to avoid port noise if at all possible.
That would work fine. I doubt you will have significant port noise.
kamberkash wrote:
also i have another question. when taking the port into consideration for enclosure volume, i would really need a box that is 2.5 cu. ft plus the volume of the port, correct?
Correct.
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