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Bike’s charging capacity

Printed From: the12volt.com
Forum Name: Motorcycle Electronics
Forum Discription: Installing Stereos, Alarms, Remote Starters, Lights, Garage Door Openers and other electronics on motorcycles.
URL: https://www.the12volt.com/installbay/forum_posts.asp?tid=139033
Printed Date: March 28, 2024 at 10:21 AM


Topic: Bike’s charging capacity

Posted By: radarcontact
Subject: Bike’s charging capacity
Date Posted: May 29, 2015 at 8:28 PM

Ok, so if my bike has a charging capacity of 448 watts, and I want to convert that to figure out how many amps it can handle, do I use:

I(A) = P(W) / V(V) -- So amps are equal to watts divided by volts

If that's right, and I do the math, I come up with ~37 amps at 12v and ~32 amps at 14v.

That seems wrong to me (a layman), because it seems like the more volts my bike is putting out, the MORE amps it should be able to "run".

Somebody set me straight, please.

Thanks so much!
Radar

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RadarContact



Replies:

Posted By: radarcontact
Date Posted: May 29, 2015 at 8:29 PM
Just FYI:

2007 Yamaha Stratoliner Midnight


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RadarContact




Posted By: icearrow6
Date Posted: May 30, 2015 at 5:13 PM
Your math is correct.
If the P(watts) doesn't change, the amps of the system to drive the wattage at the higher voltage will be less.

I think your confusion is thinking of electricity as an engine where more horsepower should yield faster car. This is more like a teeter totter. Electricity wants to balance in the same way.
448W = 12v and 37a the same as 448W = 14v and 32a. Both systems are 448Ws

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