Not really clear about the door locking system in my ford explorer i know that it's either the 5 wire alt or the reverse polarity but im not sure what i should follow because one says to cut the lines and one shows not to.
You will need to cut the wires for a 5 wire setup, reference
this diagram.
If your Ranger came with Factory Keyless it would be NEGATIVE Pulse.
If your Ranger came withOUT Factory Keyless it would be 5 wire Reversal.
If your Alarm does NOT have built in Relays: You will need 2 SPDT Relays ( Single Pole Double Throw )
5 Wire Reversal using 2 SPDT Relays:
Find your LOCK & UNLOCK wires ( PINK / Yellow & PINK / Green ) Driver Kick Panel
Cut them in Half.
One side of cut wires will have 12 Volts when you Press the DRIVER Door Switch. ( this will be called Switch Side )
One side of cut wires will show Nothing ( this will be called Motor Side )
5 Wire Reversal:
Relay 1
LOCK:
PIN 87 = 12 Volts ( + ) Constant
PIN 87a = Switch Side of cut Lock wire
PIN 30 = Motor Side of Cut Lock wire
PIN 85 = Negative Lock Output from Alarm
PIN 86 = Constant 12 volt ( + )
Relay 2
UNLOCK:
PIN 87 = 12 Volts ( + ) Constant
PIN 87a = Switch Side of Cut Unlock wire
PIN 30 = Motor Side of Cut Unlock wire
PIN 85 = Negative UnLock Output from Alarm
PIN 86 = Constant 12 volt ( + )
If your Alarm has Onboard Relays, follow it's instructions
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MO
Don't Learn from Others Mistakes
You Might Be the One That Knows.
can i use bk/w for constant power that way it's still fused on the door lock circuit?
Thanks mo12v!!! I was stumped on these door locks and your wiring description was right on!!!! Done bangin my head, thanks!!