momentary to constant?

Hey all, been awhile since I have been around, I have a question.

I am trying to make a circuit to where a momentary ground will make a signal turn on, and stay on when the car is in ON or ACC, and shut off when the key is removed. I seen this with the relay explanations and what not, and wondering if this would work . . .

IMG]https://www.the12volt.com/12voltimages/momentconstant.gif[/IMG]

Here is what I was thinking would work.

relay #1

85 - negative (-) pulse
86 - fused constant 12v+
30 - fused constant 12v+
87 - to #30 of relay #2

relay #2

85 - constant ground
86 - constant 12v+
30 - from 87 of relay #1
87 - to # 85 of relay #3

relay #3

85 - from 87 of relay #2
86 - constant ground
30 - constant fused 12v+
87 - (newly interupted when not switched on output shut off with key)


That is the correct way of accomplishing what I asked correct?

Thanks all!

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Eclipse 8445, Kicker DS60's, Hifonics TXi4400, Eclipse SW6143DVC, and Power Acoustik LT980-2.

You could do it this way-

85 - negative (-) pulse
86 - IGN switched 12v+
30 - IGN switched 12v+
87 - to #85 of relay #2

relay #2

85 - from 87 of relay #1
86 - constant ground
30 - IGN switched 12v+
87 - to # 85 relay #2
Diode between 87 and 85 of relay #2, stripe towards 85

Your 12V output will be terminal 87 of relay #2,
which turns on when you give it the momentary
ground pulse with the ignition on, and turns
off when you shut the ignition off.

thanks a lot for that, it will save me a relay or $2 lol! :)

-------------
Eclipse 8445, Kicker DS60's, Hifonics TXi4400, Eclipse SW6143DVC, and Power Acoustik LT980-2.

Actually, you don't even need the diode, just connect 85 and 87 directly, just as the diagram shows.