two second ground out without pulse timer

Guys. Without the use of a expensive pulse timer how would I go about getting the relay to hold a ground for about two second or so without a flash. I know how to make the relay change positive to negative but then I need it to hold the negative output for about two seconds. I have to use two of these so it gets pretty expensive using two pulse timers.

Diagrammes are on this site in the relay section.

delay circuit If it's a positive pulse trigger you're using as an input, and you just need a ground output maintained for a short duration after the pulse, you can try this. Just change the values of the resistor and cap to smaller values to get the short 2 sec delay. If you only need the output as a signal rather and not driving something, you can delete the relay, since the transistor puts the ground out directly. Can't get much less expensive than that, since the parts should run less than a postage stamp.

Thanks for the help guys. What I'm doing with this is using the door lock motor positive wires to drive relays to produce negative arm and disarm inputs on an alarm. I'm running into some vehicles that they flash too quick of a positive pulse for the alarm to see it. An example problem vehicle I run into is the 2004-08 F150s. The pulse seems to go so fast that it doesn't always allow the relay to fire off a long enough ground out pulse for the alarm to see it, yet if I use a Code Alarm PTM1 pulse timer set to the lowest setting (about 1 1/2 seconds) it works perfect. Just gets expensive when I need two of these timers and they cost me $14.00 each. I use a ton of them. Just trying to maybe create a circuit that I can build and save me some money and time of ordering all these timers in all the time. My distribution can't keep up with my demand for the timers and I've got waiting customers all the time because I'm waiting for the timers to come back in. The PAC TR7 is even more money.

Why a 6amp relay?  Is it because of the cap?

Yes the charging of the cap will take way more than 1 amp of current.  A 3 amp diode will probably be OK, he may have to use 10,000 mic worth of capacitor.  With that much capacitance, a 3 amp diode will probably hold up, but you know I would rather over engineer it than fix it later.

The pulse may be too short to charge up the large capacitance needed to hold the relay energized- it really needs a transistor as the relay driver, especially if there's any limitations on the drive signal current. It'll appear as a near short on the signal at the time of the pulse.

He is using the positive voltage from the door lock solenoid.  I would probably suggest the wrong transistor for the circuit, so how about a diagram?