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haemphyst

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Joined: January 19, 2003

Location: Michigan, Bouvet Island

Posted: March 16, 2012 at 4:16 PM / IP Logged

It's what we do. port - Page 3 - Last Post -- posted image.

It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

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acer9876

Member - Posts: 5

Joined: March 12, 2012

Location: Texas, United States

Posted: March 16, 2012 at 11:56 PM / IP Logged

haemphyst wrote:

A box volume specified by a driver manufacturer is a *net* volume! it can be dramatically larger in GROSS volume, however. If you need 3 cubes, you will figure 3 cubes, and then ADD TO IT. You will add to it the displacement of the driver basket and cone, the bracing, and the entire volume of the port, NOT JUST THE PORT WALLS, b_real! As you can see, your overall outside volume can be FAR greater than the 3 cubic feet specified

If you are stuck with a given outside volume, then you subtract the volume occupied by all of the above mentioned components AND the wall volume, to arrive at your net volume, which is the volume the driver interacts with.

After all that, in answer to the OPs question, you will have 3.3 cubic feet, plus the entire port volume, not wall volume.

Calculated this way:

(pi) times (radius, squared) times (height)

or: (3.1415)(r^2)(port length)

If you have a 6" port, 16 inches long, it will calculate like this:

3.1415 X 3^2 X 16

3.1415 X 9 X 16

452.4 cubic inches

452.4/1728 = .26 cubic feet.

You can see that if you don't add this, you can seriously and adversely affect the desired volume calculations.

This is the exact answer I was looking for. Thank you so much.

Getting this answer turned out to be far more complicated then I imagined. Haha. But thanks everybody for the input

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acer9876

Member - Posts: 5

Joined: March 12, 2012

Location: Texas, United States

Posted: March 17, 2012 at 12:02 AM / IP Logged

04nata wrote:

I am a layman, so let me try laymen terms <<<<<<<<<<<<delete if wrong

example:

your driver requires 3cuft volume

your port (6X16) take up .26cuft of space

your driver displacement (on mfg spec) takes up .15 cuft of space

3 + .26 + .15 = 3.41

figure your box to be 3.41cuft and after you put the prot and speaker in it will end up at the 3cuft you need.

Also a good example of what I was looking for

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