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working out 12 volt draw through inverter


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oldspark 
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Posted: May 10, 2013 at 5:48 AM / IP Logged  
Yes, power-out divided by power-in. (Times 100 if expressed as a percentage.)
[It's the same as any efficiency formula - ie, output/input.]
KPierson 
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Posted: May 10, 2013 at 2:34 PM / IP Logged  
oldspark wrote:
Yes, power-out divided by power-in. (Times 100 if expressed as a percentage.)
[It's the same as any efficiency formula - ie, output/input.]
:)
Kevin Pierson
boristhemoggy 
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Posted: May 10, 2013 at 5:44 PM / IP Logged  
KPierson wrote:
oldspark wrote:
Yes, power-out divided by power-in. (Times 100 if expressed as a percentage.)
[It's the same as any efficiency formula - ie, output/input.]
:)
I don't understand a lot of what you are saying, and I feel that my question isn't being heard let alone answered.
It must be that I simply don't understand enough to be able to grasp what you are saying.
Thanks for trying to help anyway.
oldspark 
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Posted: May 10, 2013 at 6:08 PM / IP Logged  
KP - your inbox is full. (Minor technical issue/trivia.)
Sorry boristhemoggy, it is your latter. Read through the thread again. Many things have been repeated - eg, forget nameplate ratings as they have NOTHING to do with what your PCs & laptops are actually consuming, & power P = VI [hence Pout/Pin = (Vout x Iout)/(Vin x Iin) etc].
But if you want my short conclusion - forget it - you will not be able to design a PC that consumes less or equal to that of a laptop unless you use laptop components or wait for the next generation of chips if you want a PC that is more powerful than your laptop.
But hence why I asked you WHY you had your limited power (or current?) specification.
I assume it isn't a battery reserve issue because then you probably would not be using a inverter. Nor would you use an inverter if you needed cranking ride-thru etc (not needed for a laptop, but essential for a car PC).
You should be able to google your laptop consumption... Then add ~30% to get an inverter's power input (and I = P/V from P-VI) or ~10% if using a dc-dc converter.
But read thru again and then feel free to ask for clarification or more detail.
And please use only relevant measurements and specs - not plugpack etc ratings.
PS - "efficiency" is a basic definition. See f.ex wikipedia Electrical efficiency. So too formulas like P=VI.
PPS - wiki has IMO made many pages more complex - too mathematical etc. EG, only the first part of the above link is relevant. Maybe their Electric power page is better for you (again, first section only).
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