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Ohm's Law Question


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Lebult 
Copper - Posts: 66
Copper spacespace
Joined: June 13, 2003
Location: Canada
Posted: September 07, 2003 at 9:42 PM / IP Logged  

Hey,

I'm a little confused with the Ohm's Law stuff.

What formula would I use to find the Wattage of my Amp?

I know it pumps 1000 watts @ 4 ohms using 14.4volts, but I need to find out how many Watts it'll pump at 2 Ohms using 12 volts.

An answer wouls be great, but the formula itself woulds better. I'd like to try to figure it out myself  : )

aggie altima 
Silver - Posts: 298
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Joined: July 25, 2002
Location: United States
Posted: September 08, 2003 at 2:18 AM / IP Logged  
Anybody can correct me if I'm wrong, but I believe that you can't use ohm's law using the input voltage to find power (watts).
Using the fact that the amp pumps 1000 watts @ 4 ohms using 14.4 volts, if you plug the voltage and resistance into the equation power=(volts^2)/ohms, the number you get is nowhere near 1000 watts, it actually comes out to 51.84.
Just remember that what the amplifier is doing is taking in the voltage from the battery, and then "amplifying" that voltage to a higher voltage. To use Ohm's Law, you should use the voltage measured at the speaker wires, not at the power wire. Again using the specs you gave and the voltage equation, the measured voltage at the speaker wires should be about 63 volts.
I hope this helps you in any way.
xetmes 
Silver - Posts: 586
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Joined: May 18, 2003
Posted: September 08, 2003 at 5:40 AM / IP Logged  

its not really like there is one formula to do what you want, amplifiers are all different, and do not have the exact same relationships. you could try to say that it would be less than 2000 watts because half the impedance will usually double the power, and the lower voltage would reduce that.

ohms law will not help that much because you are dealing will power.

there may be a formula out there (im not sure) it may be complicate though.

auex 
Platinum - Posts: 5,041
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Posted: September 08, 2003 at 8:37 AM / IP Logged  
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padawan 
Copper - Posts: 215
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Joined: June 11, 2002
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Posted: September 08, 2003 at 9:37 AM / IP Logged  
Power (watts) always equals the Current X the Voltage...
P=IV or P=VI.
DYohn 
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Posted: September 11, 2003 at 9:57 AM / IP Logged  
What kind of amp is it?  Generally a good manufacturer will supply the ratings you seek...
xetmes 
Silver - Posts: 586
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Joined: May 18, 2003
Posted: September 11, 2003 at 10:56 AM / IP Logged  

padawan wrote:
Power (watts) always equals the Current X the Voltage...
P=IV or P=VI.

In a traditional sence it does, but he is talking about the output of the amp to the speakers, amplifiers are not 100% efficient, and therefore a good amount of power is lost as heat depending on the efficiency it will be different.


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