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led turn light wiring


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poppago 
Member - Posts: 2
Member spacespace
Joined: June 12, 2010
Posted: June 12, 2010 at 8:47 AM / IP Logged  
I have a Winnebago Voyage that came with the high-mounted LED turn lights. Like many others, they broke at the mounting screws. So I bought some beefier replacements.
The original lights are two-wire LEDs; the replacements I bought are three-wire LEDs and I cannot figure out how to wire them. I've connected all combinations and get nothing. There are three wires: WHITE/ red, brown, and GREEN/ YELLOW.
Can anyone help?
Thanks.
Gordon
topinstaller200 
Copper - Posts: 164
Copper spacespace
Joined: June 02, 2010
Location: Florida, United States
Posted: June 14, 2010 at 9:32 PM / IP Logged  

Here is your problem. First off, your new lights should have definately came with wiring instructions. Having 3 wires---- one wire is ground--- the other 2 are probably for 2 stage lights one is energized the LEDs are on if the other is Energized the LEDs become brighter.

Your second issue is that you need to test which wire does what on your camper 1 is ground the other is 12V when you hit the turn signal.Basic test light should suffice here.

you may have initially hooked your LEDs up wrong on your first attempt. Thus permanantly damaging your LEDs. LEDs are polarity sensitive. You hook them up right and they light up, you reverse the wires and you just blew all your LEDs, no-smoke, no-flash, no-smell

Before you send you LEDs back hook the on a TEST bench(ie: a 12V battery and 2 wire leads)

poppago 
Member - Posts: 2
Member spacespace
Joined: June 12, 2010
Posted: June 15, 2010 at 11:16 AM / IP Logged  
Thanks for your help. I did finally figure out the wiring: GREEN/ YELLOW is brake/turn (bright), brown is tail (dim), and WHITE/ red is ground.
A couple of comments:
Lights came with no instructions or diagrams.
Several people commented about damage, but that did not happen. They are polarized: hook up right, get light; hook up wrong, get nothing, including no damage. That’s what I’d expect from a diode.
Thanks.
Gordon

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