DVC winding

How are most dual voice coil subs wound?  I was curious if I power one voice coil how mauch power would be present across the terminals of the other voice coil.  I would like to model the voice coil so I can calculate it. I know it is minimal from what I have read, but my professor needs proof.  Thanks.Good Luck!

-Thad

They are two wires, concentrically wound and electrically isolated, on an iron core. Sounds like a 1:1 transformer to me... This being said, there are relatively few windings available, so the current sourcing capabilities of the "secondary" or second voice coil will be low, thus little "power" ability. With the coil unshorted or unloaded, the voltage produced on by the secondary should be similar to the voltage applied to the primary. My answer, though: a few watts at best, depending on the woofer geometry, i.e. core size, turns of wire, how closely the coils are coupled to the core and each other... MANY things will provide you with a different answer. I have never actually done physical experiments to confirm this, but this is the way I would THINK it'd happen. The windings are perhaps 100 turns or so, per voice coil. It will be diferent per manufacturer and model of woofer. If you can find out the size of wire used to wire the coil, and you know the diameter of the former, and you know the DCR of the coil, it would be a fairly simple process to extrapolate the number of turns contained in the coil.It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

I wonder if this: http://www.mhsoft.nl/Mysystem/Reactance.asp might help.  And I wonder, too, if the efficiency of the driver itself would play a role in the amount of power that would be present through the unused coil.Build the box so that it performs well in the worst case scenario and, in return, it will reward you at all times.

stevdart wrote: And I wonder, too, if the efficiency of the driver itself would play a role in the amount of power that would be present through the unused coil.

Tha's a good question, but I don't think so. Efficiency (No, or eta naught) is the amount of electrical energy is actually converted to sound... I don't believe that would have any influence on coupling... but that's just me. We haven't heard Steven chime in here yet... I bet he's got some input! No, thinking about it further, it wouldn't. The efficiency of the driver is X. This number can ONLY exist when the voice coils are INSIDE the magnetic field. Remove the magnetic field (but NOT the pole piece), efficiency would drop to zero, but the coupling, inductance, complex impedance... none of those would change. As long as the coils are not PHYSICALLY moved from their position on, in, around, the pole piece, energy transfer from coil to coil would not change...It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

The power generaterd into the second unused voice coil will be low, less than 5 watts.Support the12volt.com

hehe DYohn said 'terd' LOLIt all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."

Thanks guys that should get a me a start on it. My professor is a home audio guy so dvc is fairly new to him. He was trying to get me to calculate it like they are in parallel and I just couldn't convice him that they are not. I was doing some calculations for resistively damped operation and he said it was unfeasible in my application because the power handling of the potentiometer would have to be large and therefore it would be expensive. I appreciate the input of you experts. Good Luck!

-Thad

haemphyst wrote: hehe DYohn said 'terd' LOL

Sometimes I am one, too. 

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