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sizotty 
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Joined: April 29, 2007
Location: United States
Posted: April 29, 2007 at 11:12 PM / IP Logged  

i have a 10 inch JL W6...

a DVC sub both with 4ohms.

i also have a MTX Blut Thunder Pro300x2 amp.

RMS Power measured at 12.5 Volts DC:

150 watts x 2 into a 4 ohm load with less than 0.05% THD+N
300 watts x 2 into a 2 ohm load with less than 0.1% THD+N
600 watts bridged into a 4 ohm load with less than 0.1% THD+N
Dynamic Power (IHF-202 standard) measured at 14.4 Volts DC:
200 watts x 2 into a 4 ohm load
375 watts x 2 into a 2 ohm load
750 watts bridged into a 4 ohm load

now i have my subs coils wired in parallel for 2ohms. i believe. and im trying to figure out how to pull the bridged power out of my amp. and if that is possible with only one sub. please help. diagrams would be nice.

10" JLW6V2
MTX Blue Thunder Pro300X2
brandonklassen 
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Location: Canada
Posted: April 29, 2007 at 11:51 PM / IP Logged  
to bridge the amp you need to take the + terminal on the first channel to the + on th sub, and the - terminal on the second to the - on the sub.
brandonklassen 
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Posted: April 29, 2007 at 11:54 PM / IP Logged  

ignore that i forgot it was a dvc sub

aznboi3644 
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Posted: April 30, 2007 at 12:45 AM / IP Logged  
use the woofer wiring link on the left of the screen
Alpine Guy 
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Posted: April 30, 2007 at 8:59 AM / IP Logged  
A single dvc 4 ohm sub? Wont work bridged on a 2 ohm load, you can only get a 2 ohm, or 8 ohm impedance on that sub so you will have to wire it in series to get a 2 ohm load and attach it normally to either the left or right channel of the amp. Or wire the sub in parallel to get a 8 ohm load and bridge it on the amp.
How to bridge the amp is listed in your manual, or on the downloadable manuals on mtxaudio.com. To get the 8 ohm load you simply just hook both positive inputs on the sub to the positive bridged output on the amp, and both negative inputs on the sub to the negative bridged input on the amp.
2003 Chevy Avalanche,Eclipse CD7000,Morel Elate 5,Adire Extremis,Alpine PDX-4.150, 15" TC-3000, 2 Alpine PDX-1.1000, 470Amp HO Alt.
jstruckman 
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Posted: April 30, 2007 at 11:06 AM / IP Logged  
Uh.....NO. If you wire the positive of the sub to the positive of the amp and the negative of the subs to the negative on the amp, that will be a 2 0hm load, this is parallel wiring, series is wiring positive of coil 1 to negative of coil 2, you have it backwards Alpine guy.
aznboi3644 
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Posted: April 30, 2007 at 12:37 PM / IP Logged  
just wire each coil to a channel and be done with it
sedate 
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Posted: April 30, 2007 at 2:45 PM / IP Logged  

aznboi3644 wrote:

just wire each coil to a channel and be done with it

He should bridge the amplifier to sum the signal .. this is preferable over individually wiring each voice coil.

Alpine Guy wrote:
Or wire the sub in parallel to get a 8 ohm load and bridge it on the amp.

Alpine Guy obviously meant 'series.'  This is the proper way to wire this. This will sum the signal, as well as produce the highest power output with the lowest THD.

"I'm finished!" - Daniel Plainview
Alpine Guy 
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Posted: April 30, 2007 at 7:05 PM / IP Logged  
Ya, sorry I meant series, I totally got that wireing backwards haha. I just wrote a 2 hour 3 phase gen, load, and transformer exam before I wrote that this morning, I still can't tie my shoes and it's supper time lol.
2003 Chevy Avalanche,Eclipse CD7000,Morel Elate 5,Adire Extremis,Alpine PDX-4.150, 15" TC-3000, 2 Alpine PDX-1.1000, 470Amp HO Alt.

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