# w6 or 2 type r's

bwhvac065@aol.c
Copper - Posts: 67
Joined: April 05, 2009
Location: Indiana, United States
Posted: April 11, 2009 at 12:37 AM / IP Logged
ok i have a question since everyone seems to be having a good day.LOL i have six punch p2s 12s how would you measure the cone area?
Blazerspl
6 rockford 12s
5500 watt pa amp
12.0 cubic enclosure
BIG 3
whiterob
Copper - Posts: 351
Joined: July 22, 2007
Location: United States
Posted: April 11, 2009 at 12:43 AM / IP Logged
bwhvac065@aol.c wrote:
 ok i have a question since everyone seems to be having a good day.LOL i have six punch p2s 12s how would you measure the cone area?
Look at the specs of your sub and look for a value that is called "Sd". That is the effective cone area of your sub. Then just multiply that number by 6 and you have the total cone area of your subs.
Otherwise you can just do the area of a circle (A = pi * radius^2) to give you a basic idea. It won't be perfect but it will be close enough.
bwhvac065@aol.c
Copper - Posts: 67
Joined: April 05, 2009
Location: Indiana, United States
Posted: April 11, 2009 at 12:47 AM / IP Logged
ok thanks. On the equasion above pi is 3.14?
Blazerspl
6 rockford 12s
5500 watt pa amp
12.0 cubic enclosure
BIG 3
bwhvac065@aol.c
Copper - Posts: 67
Joined: April 05, 2009
Location: Indiana, United States
Posted: April 11, 2009 at 12:48 AM / IP Logged

if not can you possibly do a demo of the correct equasion? either way thanks for your time

Blazerspl
6 rockford 12s
5500 watt pa amp
12.0 cubic enclosure
BIG 3
haemphyst
Platinum - Posts: 5,054
Joined: January 19, 2003
Location: Michigan, Bouvet Island
Posted: April 11, 2009 at 1:02 AM / IP Logged
diameter of the driver / 2 = r
(I measure from the center of the surround roll to the opposite center)
EX: a 15" driver, will measure about 13" across, so 13 / 2 = 6.5
3.141592 * (6.5 ^2) = Sd
3.141592 * 42.25 = Sd
3.141592 * 42.25 = 132.73 in^2
132.73 * 6 = 796.4 in^2 of total surface area, for six 15's.
An easier way, though, would be to use the manufacturer's specified Sd, and multiply by the number of drivers you want to use.
It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice.﻿ You should write it down."
whiterob
Copper - Posts: 351
Joined: July 22, 2007
Location: United States
Posted: April 11, 2009 at 1:03 AM / IP Logged
bwhvac065@aol.c wrote:
 if not can you possibly do a demo of the correct equasion? either way thanks for your time
An example would be...
A = 3.1415 x 5.5^2 = 95 square inches of cone area.
95 x 6 subs = 570 square inches of total cone area.
The 5.5 value refers to a 5.5 inch radius. The cone are will not include the entire sub so I just made up a value that I figured would be close to the radius you would use for a 12" sub.
bwhvac065@aol.c
Copper - Posts: 67
Joined: April 05, 2009
Location: Indiana, United States
Posted: April 11, 2009 at 1:05 AM / IP Logged
damn that is alot of math i think i will go with the SD. Thanks a million fellas
Blazerspl
6 rockford 12s
5500 watt pa amp
12.0 cubic enclosure
BIG 3
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