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capacitance calculator


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jeffchilcott 
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Joined: April 11, 2002
Location: United States
Posted: April 28, 2009 at 11:11 PM / IP Logged  
can anyone help me out here, I used to have some equations.   Cant seem to find them, trying to see if something is plausible
Trying to solve farads of capacitance (c)it would take to support (x)Amps at (y) voltage for (t) time
So
Farads = 900Amps 14volts for 3 seconds
thanks for any help
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haemphyst 
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Joined: January 19, 2003
Location: Michigan, Bouvet Island
Posted: April 29, 2009 at 12:07 AM / IP Logged  
IIRC from all those years of electrical training in the Navy... (This is a formula I don't often use...)
Amps times Volts times Time = Joules or watt-seconds
900 X 14 X 3 = 37.8kJ
Joules / Volts = Farads
37800 / 14.4 = 2625F
So... 900A at 14.4V for 3 seconds would require 2.6kF!
Pretty sure that's the way it works... If I'm wrong, i am an idiot will be along shortly to give you the correct information... :)
It all reminds me of something that Molière once said to Guy de Maupassant at a café in Vienna: "That's nice. You should write it down."
DYohn 
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Joined: April 22, 2003
Location: Arizona, United States
Posted: April 29, 2009 at 11:02 AM / IP Logged  

That sounds about right.

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