cubic feet 8 jl w3 sub fiber glass enlc

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antwone230

Member - Posts: 8

Joined: October 13, 2010

Location: United States

Posted: October 13, 2010 at 1:30 AM / IP Logged

I am making a custom fiber glass enclosure for my 8 inch JL audio W3 and I am not sure on how much air space this sub needs to be on the inside? I am putting the enclosure in the back right rear of the trunk.

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antwone230

Member - Posts: 8

Joined: October 13, 2010

Location: United States

Posted: October 13, 2010 at 10:03 AM / IP Logged

Alright in a sealed enclosure the volume would be 0.3. Do I have to add the Driver Displacement: which is 0.03 . Do I combine both numbers for my total enclosure internal area?

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mrm1776

Copper - Posts: 100

Joined: October 08, 2010

Location: Texas, United States

Posted: October 13, 2010 at 12:53 PM / IP Logged

It should be the volume AFTER you've removed the displacement of the woofer. So 0.33 is what you should aim for. This is just going off of the numbers you gave me.

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icearrow6

Copper - Posts: 497

Joined: February 02, 2009

Location: California, United States

Posted: October 13, 2010 at 5:19 PM / IP Logged

Also don't forget to take into account the displacement of the woofer itself.

So:

.3 (your goal) = Total Volume - Bracing - woofer volume.

antwone230

Member - Posts: 8

Joined: October 13, 2010

Location: United States

Posted: October 14, 2010 at 1:30 AM / IP Logged

so you mean if the box is 3 cubic feet and then when i put the sub in that subtracts from the 3 cubic feet so i have to compensate for the lost volume?

I am really confused on this box volume and how big i need for it to be.

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Alpine Guy

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Joined: October 18, 2003

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Posted: October 14, 2010 at 8:00 AM / IP Logged

You need a .33 cu.ft box to compensate for the driver displacement.

2003 Chevy Avalanche,Eclipse CD7000,Morel Elate 5,Adire Extremis,Alpine PDX-4.150, 15" TC-3000, 2 Alpine PDX-1.1000, 470Amp HO Alt.

mrm1776

Copper - Posts: 100

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Location: Texas, United States

Posted: October 14, 2010 at 10:23 AM / IP Logged

Alpine Guy wrote:

You need a .33 cu.ft box to compensate for the driver displacement.

Or slightly bigger depending on how much bracing you do. 0.33 is a pretty small box though so you shouldn't have to do a ton of internal bracing.

MECP Basic Installation Tech

Certification ID: CEA195600

Pioneer AVIC-X920BT

Polk Audio DXi 6500 - front

Rockford Fosgate Power T1693 - rear

Alpine MRP-F300

Alpine MRP-M500

Alpine SWR-1242D

icearrow6

Copper - Posts: 497

Joined: February 02, 2009

Location: California, United States

Posted: October 14, 2010 at 12:19 PM / IP Logged

Yes:

(woofer displacement) + (internal bracing) + (target net volume) = TOTAL VOLUME your box needs to have.

Example:

.3 Qft (woofer) + .5Qft (bracing) + 3 Qft (desired airspace) = 3.8Qtf (total air space needed)

antwone230

Member - Posts: 8

Joined: October 13, 2010

Location: United States

Posted: October 14, 2010 at 3:24 PM / IP Logged

to make .30 ft............... 12in x 10in x 8in (Width x height x Depth)

305mm x 254 x 203mm

Is this correct guys?

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Alpine Guy

Platinum - Posts: 2,478

Joined: October 18, 2003

Location: Canada

Posted: October 14, 2010 at 4:41 PM / IP Logged

antwone230 wrote:

to make .30 ft............... 12in x 10in x 8in (Width x height x Depth)

305mm x 254 x 203mm

Is this correct guys?

That would be .33 if those measurements are outside measurements, and the enclosure wall thickness is 3/4"

2003 Chevy Avalanche,Eclipse CD7000,Morel Elate 5,Adire Extremis,Alpine PDX-4.150, 15" TC-3000, 2 Alpine PDX-1.1000, 470Amp HO Alt.

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