door locks, trunk release wiring

Does this diagram look right? Diagrame (beware 56k) Basically what I want to do is put in 4 2-wire door lock actuators and a trunk actuator. The trunk actuator only needs to pull, so therefore I'd ground one side and power the other. The car currently has no power locks or trunk I'm wiring into - I'm adding this all new. The door lock ones need to switch power and ground depending on whether they're pushing or pulling, so I wired them up with the relays and the diodes. the relay gives ground to one while the other is powered by either the momentary switch being pressed, or the alarm sending signal to the relay. Does this look right? If so - what kind of diodes do I need to get. If not - what should I change? The diodes are necessary so when I power one side it's not putting 12V into the ground on the other side, right? Sorry for the crappy picture - I took it with my digital camera of something I drew. I'm going to use the scanner when I get to work and re-upload it.

2 SPDT Relays:

Relay 1

LOCK:

PIN 87 =  12 Volts ( + ) ConstantPIN 87a = GROUNDPIN 30 =  wire to Lock side or Down of ActuatorsPIN 85 = Negative Lock Output from Alarm or SwitchPIN 86 = Constant 12 volt ( + )

Relay 2

UNLOCK:

PIN 87 =  12 Volts ( + ) ConstantPIN 87a = GROUNDPIN 30 =  wire to Unlock side or Up of ActuatorsPIN 85 = Negative UnLock Output from Alarm or SwitchPIN 86 = Constant 12 volt ( + )

I want the switches to lock/unlock from in the car without having to use the module. If I wired the switches to grounds for the switches - wouldn't I have to put ground to 87 and 12V to 87a?2003 Dodge Neon SE

K&N + CAI

Power locks, trunk and some LEDs soon.

Joe, Are you saying what I have is right? That's how I have it wired (minus the diodes)2003 Dodge Neon SE

K&N + CAI

Power locks, trunk and some LEDs soon.

Wire as I postedIf you are using 2 wire Actuators for all 4 Doors.........You will be switching + to 1 side of Actuators via 1 Relay while giving Ground to other side of Actuators via the other relay & Visa Versa

As I see it the problem would be when i activate the switch to give + to one side of the relay, I'd be putting + INTO the 30 pin, which if the alarm wasn't activated would be sitting on the 87a input for both, which would be ground. Wouldn't passing 12V+ into a ground wire (even if it's also going into the actuator) blow my fuse? I'm starting to think that putting the switches on the alarm lines, and linking them to a ground as well, may be the best way to go. --Jimmy2003 Dodge Neon SE

K&N + CAI

Power locks, trunk and some LEDs soon.

PIN 87a & 30 stand at closed or connected together internallyWhen Relay is activated PIN 87 & 30 close or are connected.So when you activate Lock Relay 1, it supplies 12 volt + to PIN 30 which goes to Lock side wire of 2 wire Actuator .... Unlock Relay 2 stays at GROUND which would supply GROUND to GROUND side ( Unlock wire if you will ) wire of 2 ( or second wire ) wire Actuator

If you look at my diagram you'll see the lock/unlock switches over to the left. They do not use the relay are are connected directly between the 30 wire of each relay and the 12V source. Therefore, if neither relay was activated, and one of the switches WAS activated, I'd be putting 12V+ through the relay into ground because the relay would be at rest on 87a.2003 Dodge Neon SE

K&N + CAI

Power locks, trunk and some LEDs soon.

Sorry hit post too quickly - In short - moving the switches to the 85-pin side of the relay will solve my problemo. No diodes required.2003 Dodge Neon SE

K&N + CAI

Power locks, trunk and some LEDs soon.