# Bike's charging capacity

Copper - Posts: 54
Joined: June 16, 2009
Location: Florida, United States
Posted: May 29, 2015 at 8:28 PM / IP Logged
Ok, so if my bike has a charging capacity of 448 watts, and I want to convert that to figure out how many amps it can handle, do I use:
I(A) = P(W) / V(V) -- So amps are equal to watts divided by volts
If that's right, and I do the math, I come up with ~37 amps at 12v and ~32 amps at 14v.
That seems wrong to me (a layman), because it seems like the more volts my bike is putting out, the MORE amps it should be able to "run".
Thanks so much!
Copper - Posts: 54
Joined: June 16, 2009
Location: Florida, United States
Posted: May 29, 2015 at 8:29 PM / IP Logged
Just FYI:
2007 Yamaha Stratoliner Midnight
icearrow6
Copper - Posts: 497
Joined: February 02, 2009
Location: California, United States
Posted: May 30, 2015 at 5:13 PM / IP Logged
If the P(watts) doesn't change, the amps of the system to drive the wattage at the higher voltage will be less.
I think your confusion is thinking of electricity as an engine where more horsepower should yield faster car. This is more like a teeter totter. Electricity wants to balance in the same way.
448W = 12v and 37a the same as 448W = 14v and 32a. Both systems are 448Ws

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